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In a group of 80 music lovers, 40 people liked modern songs and 30 % liked modern songs but not folk songs.find: If 30 people liked flok songs only,how many people did not like both types of songs?​

1 Answer

4 votes

Answer:

20 people

Explanation:

Let A be the set of people who liked modern songs, and B be the set of people who liked folk songs. Let x be the number of people who liked both modern and folk songs, and y be the number of people who liked modern songs but not folk songs.

We are given the following information:

|A| = 40 (40 people liked modern songs)

|B| = y + x + 30 (30% of the group liked modern songs but not folk songs, which means that the remaining 70% liked folk songs either exclusively or in combination with modern songs. So, |B| = 0.7 * 80 = 56, and we can express this in terms of x and y as y + x + 30 = 56.)

|B\A| = 30 (30 people liked folk songs only)

We want to find the number of people who did not like either modern or folk songs, which is the complement of the set (A U B). We can use the formula for the size of the union of two sets:

|A U B| = |A| + |B| - |A intersect B|

Substituting the values we have, we get:

80 - |A U B| = 40 + (y + x + 30) - x

Simplifying, we get:

80 - |A U B| = 70 + y + 30

Simplifying further, we get:

|A U B| = 40 - y - x

We also know that:

|B\A| = 30

Substituting the formula for the set difference, we get:

|B| - |A intersect B| = 30

Substituting the values we have, we get:

y + x + 30 - x = 30

Simplifying, we get:

y = 0

This means that no one liked modern songs but not folk songs.

Substituting y = 0 into the equation for |A U B|, we get:

|A U B| = 40 - x

Substituting this into the equation we derived earlier, we get:

80 - (40 - x) = 70 + 0 + 30

Simplifying, we get:

x = 20

So, the answer is 20 people.

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User Niti
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