Question

12345678 x

2
How do the areas of the parallelograms compare?
O The area of parallelogram 1 is 4 square units greater
than the area of parallelogram 2.
The area of parallelogram 1 is 2 square units greater
than the area of parallelogram 2.
O The area of parallelogram 1 is equal to the area of
parallelogram 2.
The area of parallelogram 1 is 2 square units less
than the area of parallelogram 2.

Answer 1

B. The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2.

Explanation:

Parallelogram 1:

Base = 12345678

Height = 2 (multiplier)

Area = Base × Height = 12345678 × 2 = 24691356 square units

Parallelogram 2:

Base = 12345678

Height = 1 (multiplier)

Area = Base × Height = 12345678 × 1 = 12345678 square units

Now, let's compare the areas:

The area of parallelogram 1 is 24691356 square units, and the area of parallelogram 2 is 12345678 square units. The area of parallelogram 1 is twice the area of parallelogram 2.

Therefore, the correct option is:

B. The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2.