Question

a drop of oil of volume 10^_10m^3 spreads out water to make a circular film of radius 10^_1m. what is the thickness of the film.​

Answer 1

The answer is 10^-6 m

A step-by-step solution is below:

The volume of the oil is 10^-10 m^3. The radius of the oil film is 10^-1 m. The thickness of the oil film is the volume divided by the area. The area of a circle is pi * r^2. The thickness of the oil film is 10^-10 m^3 / (3.14 * 10^-2 m^2) = 10^-6 m.