Question

The cable passes over a frictionless pulley located at C. Neglect the size of this pulley and weight of the boom. (Figure 1).

Calculate the tension in the cable at BB required to support the load of mmm = 200 kg.
Express your answer to three significant figures and include the appropriate units.

Answer 1

To calculate the tension in a cable supporting a 200 kg load at equilibrium, multiply the mass by the acceleration due to gravity, which yields a tension of 1962 N.

Step-by-step explanation:

The student's question pertains to the calculation of the tension in a cable system, which is a concept in classical mechanics, a branch of physics. The given scenarios involve determining the tension that supports a load or maintains equilibrium in a static or dynamic situation.

For instance, calculating the tension in a cable that supports a 200 kg load can be done by using Newton's second law. Assuming the system is in equilibrium, the tension T would equal the weight of the load, which is m*g, where m is the mass (200 kg) and g is the acceleration due to gravity (approximately 9.81 m/s2). Therefore, T = 200 kg * 9.81 m/s2 = 1962 N.

In problems where the system is not static, the tension would need to be calculated by considering the additional acceleration of the system. These require a free-body diagram and application of Newton's laws, taking into account the mass of the objects and the acceleration they undergo.

Answer 2

To find the tension in the cable at BB, we need to consider the forces acting on the boom and the load. Since the pulley is frictionless and the weight of the boom is neglected, the only force acting on the boom is the tension in the cable.

Step-by-step explanation:

To calculate the tension in the cable at BB, we need to consider the forces acting on the boom and the load. Since the pulley is frictionless and the weight of the boom is neglected, the only force acting on the boom is the tension in the cable. The weight of the load acts vertically downward, and the tension in the cable pulls it upwards.

By applying Newton's second law, we can determine the tension in the cable. The tension in the cable is equal to the weight of the load, which is 200 kg, multiplied by the acceleration due to gravity, approximately 9.8 m/s^2. Therefore, the tension in the cable at BB is 200 kg * 9.8 m/s^2 = 1960 N.