Final answer:
The angle between the Cerenkov radiation shock wave and the electron's direction of motion, when the electron travels through water at a speed 10% faster than the speed of light in that medium, is approximately 24.6°.
Step-by-step explanation:
The student is asking about Cerenkov radiation and the angle formed between the shock wave (or light cone) and the direction of an electron's motion as it passes through water at a speed greater than the speed of light in that medium. To find this angle, we can use the Cerenkov radiation condition which states that the radiation occurs when a charged particle (like an electron) moves through a dielectric medium at a speed greater than the phase velocity of light in that medium. Since the speed of light in water is approximately 0.75c, and the electron is moving at 1.10c (10% faster), we can use the equation derived from the Cerenkov effect: cos(θ) = β∑1, where θ is the angle between the shock wave and the electron's direction of motion and β is the velocity of the particle divided by the speed of light in the same medium.
The angle θ can be calculated using the expression 1/β, which equals the ratio of the speed of light in water to the electron's speed. Since β is 1.10 (the speed of the electron is 1.10 times the speed of light in water), the calculation becomes cos(θ) = 1/1.10, which simplifies to cos(θ) = 0.909. Using the inverse cosine function, we find that θ is approximately 24.6°. Therefore, the angle between the shock wave and the electron's direction of motion is approximately 24.6°.