Question

Solve each equation for θ with 0 ≤ θ <2π. 4 sinθ + 2 √3 =0

Answer 1

`4\sin \theta+2\sqrt 3=0\\\\4\sin \theta=-2\sqrt 3 \\\\\sin \theta=-(\sqrt 3)/(2)\\\\\boxed{\theta=(4\pi)/(3), (5\pi)/(3)}`