Question

A number is 5 more than 3 times another number. The sum of the two numbers is 33. As an equation, this is written x + 3x + 5 = 33, where x represents the smaller number. Plug in the numbers from the set {3, 5, 7, 9} to find the value of x.

The value of x that holds true for the equation is
. So, the smaller number is
and the larger number is
.

Answer 1

the smaller number is 7, and the larger number is 3(7) + 5 = 26.

Explanation:

Let's substitute the numbers from the set {3, 5, 7, 9} into the equation x + 3x + 5 = 33 to find the value of x.

For x = 3:

3 + 3(3) + 5 = 3 + 9 + 5 = 17, which is not equal to 33.

For x = 5:

5 + 3(5) + 5 = 5 + 15 + 5 = 25, which is not equal to 33.

For x = 7:

7 + 3(7) + 5 = 7 + 21 + 5 = 33, which is equal to 33.

For x = 9:

9 + 3(9) + 5 = 9 + 27 + 5 = 41, which is not equal to 33.

Therefore, the value of x that holds true for the equation x + 3x + 5 = 33 is x = 7. So, the smaller number is 7, and the larger number is 3(7) + 5 = 26.

Answer 2

the smaller one is 3 and the big one is 7

Explanation: