Question

Force 1 is supposed to be [100.0 grams-g, 60.0 °) and Force 2 is supposed to be [200.0 grams - g

120.0°). You will apply a third force to balance the system--how much force should you
apply?

Answer 1

Step-by-step explanation:

You have to 'balance' the vertical and horizontal forces with an equal but opposite third force .....

vertical : 100 sin60 + 200 sin (120) = 259.8 N

Horizontal 100 cos 60 + 200 cos 120 = -50 N

Magnitude = sqrt ( 259.8^2 + (-50)^2) = 264.57 N

The vertical and horizontal components will be opposite the ones found above :

angle = arc tan -259.8 / (50) = 280.9 degrees