asked 92.2k views
3 votes
What is the quotient of (x³ - 3x² + 5x - 3) + (x - 1)?

Ox²-2x-3
Ox²+2x+7
Ox²-3x+8
Ox²-2x+3

asked
User Carstenj
by
7.7k points

1 Answer

2 votes

Answer:

(d) x² -2x +3

Explanation:

You want the quotient (x³ - 3x² + 5x - 3) ÷ (x - 1).

Quick Check

The constant in a product will be the product of the constants in the factors. That is if (x² +bx +c) is a factor of the cubic, we must have ...

-1·c = -3 . . . . . . . where the other factor is (x -1), having constant -1

c = 3

Only one answer choice matches: x²-2x+3.

Synthetic division

Using synthetic division to find the entire quotient can be almost as fast.

The tableau is shown in the attachment. It tells you the quotient is ...

x² -2x +3

__

Additional comment

"The entry in the left part of the table" is the zero of the binomial divisor. The divisor (x-1) is zero when x=1, so that entry is 1.

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What is the quotient of (x³ - 3x² + 5x - 3) + (x - 1)? Ox²-2x-3 Ox²+2x+7 Ox²-3x+8 Ox-example-1
answered
User Victor Grazi
by
8.4k points

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