Question

How many moles of O2 are produced when 8 g of CH4 react in the following equation?

CH4 + 2 02 --> CO₂ + 2 H₂O
→
O2 moles
O 0.5 moles
O 8 moles
O 1 mole
O 0.25 moles

Answer 1

1 mole

Step-by-step explanation:

The balanced chemical equation for the reaction is:

CH4 + 2O2 → CO2 + 2H2O

The stoichiometric coefficients of the reactants and products indicate that one mole of methane reacts with two moles of oxygen gas to produce one mole of oxygen gas.

To find the number of moles of O2 produced when 8 g of CH4 react, we first need to convert the mass of CH4 to moles. The molar mass of CH4 is 16 g/mol. Therefore,

8 g CH4 × (1 mol CH4/16 g CH4) = 0.5 mol CH4

According to the balanced equation, 1 mole of methane reacts with 2 moles of oxygen gas. Therefore,

0.5 mol CH4 × (2 mol O2/1 mol CH4) = 1 mol O2

So, 1 mole of O2 is produced when 8 g of CH4 react in this equation.