Question

3x+y= 34 & x+y=10 solve by substitution or elimination

Answer 1

x = 12 and y = -2.

Explanation:

Let's solve the system of equations using the method of substitution:

Given equations:

3x + y = 34

x + y = 10

We can solve equation 2) for y:

y = 10 - x

Now substitute this value of y into equation 1):

3x + (10 - x) = 34

Simplify:

3x + 10 - x = 34

2x + 10 = 34

Subtract 10 from both sides:

2x = 24

Divide both sides by 2:

x = 12

Now substitute the value of x back into equation 2) to find y:

12 + y = 10

Subtract 12 from both sides:

y = -2

Therefore, the solution to the system of equations is x = 12 and y = -2.

Answer 2

The answer is:

(12, -2)

Work/explanation:

I am going to use substitution and solve the second equation for x.

x + y = 10

x = 10 - y

Now, plug in 10 - y into the first equation.

3x + y = 34

3(10 - y) + y = 34

Simplify

30 - 3y + y = 34

30 - 2y = 34

-2y = 34 - 30

-2y = 4

y = -2

Plug in -2 into any of the two equations to solve for "x".

x + (-2) = 10

x - 2 = 10

x = 12

Hence, the answer is (12, -2).