Answer:
The balanced reaction between aqueous potassium hydroxide (KOH) and aqueous acetic acid (CH3COOH) is a neutralization reaction, which is a type of double displacement or metathesis reaction. In this reaction, an acid reacts with a base to produce water and a salt. The general form of a neutralization reaction is:
Acid + Base → Salt + Water
In the case of the reaction between potassium hydroxide and acetic acid, the products are water (H2O) and potassium acetate (KC2H3O2). The balanced chemical equation for this reaction is:
CH3COOH(aq) + KOH(aq) → KC2H3O2(aq) + H2O(l)
This equation is balanced because there are equal numbers of each type of atom on both sides of the equation. On the left side (the reactants), there are 2 carbon atoms, 4 hydrogen atoms, 1 potassium atom, and 3 oxygen atoms. On the right side (the products), there are also 2 carbon atoms, 4 hydrogen atoms, 1 potassium atom, and 3 oxygen atoms.