Question

Consider the arithmetic sequence 21, 30, 39, 48, … and determine the number of terms that lie between

390 and the 29th term.​

Answer 1

The numbers are 282,291,300,309,318,327,336,345,354,363,372,381,

Common rhg
`t(29) = 21 + (29 - 1)9`

`= 21 + (28)9`

=21+252

=273

The numbers are 282,291,300,309,318,327,336,345,354,363,372,381

Answer 2

first add 390 to 29 then, divided it to the sequence and there's your answer