Check the picture below.
since we know that AB = AD, twin sides will yield twin angles, that means that ∡ADB is a twin angle to ∡ABD.
Now, the two angles at vertex D are linear angles, so their sum is 180°, and since we know that BA = BC, twin sides make twin angles, meaning that ∡A and ∡C are twins, and if we know that a triangle has a total 180° for is interior angles, that means that 36° + 36° + 72° + "the gap above" = 180°, so that gap above must be 36°.
Anyhow, that leaves triangle BCD with a couple of twin angles, yielded by twin sides.