Question

Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p . \[ n=122, p=0.73 \]

Answer 1

Given n = 122 and p = 0.73, we can find the mean, variance, and standard deviation of the binomial distribution using the following formulas:

mean = np

variance = np(1-p)

standard deviation = sqrt(np(1-p))

Substituting the given values into these formulas, we get:

mean = np = 122 x 0.73 = 89.06

variance = np(1-p) = 122 x 0.73 x (1-0.73) = 24.13

standard deviation = sqrt(np(1-p)) = sqrt(122 x 0.73 x (1-0.73)) = 4.91

Therefore, the mean of the binomial distribution is 89.06, the variance is 24.13, and the standard deviation is 4.91.