Answer:
Equation of the line with points (-9, 1) and (-3, 2): y = 1/6x + 5/2
slope = 1/6
y-intercept = 5/2
Explanation:
- Given two points, we can find the line passing through the points in slope-intercept form, whose general equation is given by:
y = mx + b, where
- m is the slope,
- and b is the y-intercept.
Step 1: Find m, the slope:
- We can find the slope using the slope formula, which is given by:
m = (y2 - y1) / (x2 - x1), where
- (x1, y1) are one point on the line,
- and (x2, y2) is another point on the line.
Thus, we can plug in (-9, 1) for (x1, y1) and (-3, 2) for (x2, y2):
m = (2 - 1) / (-3 - (-9))
m = 1 / (-3 + 9)
m = 1/6
Step 2: Find b, the y-intercept:
- We can find b, the y-intercept by plugging in 1/6 for m and one of the points for (x, y) in y = mx + b.
Let's use (-9, 1):
1 = 1/6(-9) + b
1 = -3/2 + b
5/2 = b
Thus, the equation of the line containing points (-9, 1) and (-3, 2) is y = 1/6x + 5/2, where 1/6 is the slope and 5/2 is the y-intercept.