Question

if 9.00g grams of gas are enclosed in a 50.00 L vessel at 273.15K and 2.000 atmospheres of pressure , what is the molar mass of the gas? what gas is this?

Answer 1

Answer: 4.88 g/mol. and helium

Step-by-step explanation:

To find the molar mass of the gas, we can use the ideal gas law equation which is PV=nRT where:

P = pressure = 2.000 atm

V = volume = 50.00 L

n = number of moles

R = gas constant = 0.08206 L·atm/K·mol

T = temperature = 273.15 K

First, we need to find the number of moles of the gas:

PV = nRT

n = PV/RT

n = (2.000 atm)(50.00 L)/(0.08206 L·atm/K·mol)(273.15 K)

n = 1.844 mol

Now, we can find the molar mass of the gas by dividing its mass by the number of moles:

molar mass = mass/number of moles

mass = 9.00 g

molar mass = 9.00 g/1.844 mol

molar mass = 4.88 g/mol

Therefore, the molar mass of the gas is 4.88 g/mol.

To determine what gas this is, we can compare the molar mass of the gas to the molar masses of known gases. The molar mass of 4.88 g/mol is closest to that of helium (4.00 g/mol). Therefore, this gas is most likely helium.