Question

The circle below is centered at the point (3, 1) and has a radius of length 2.

What is its equation?
5
O A. (x+ 1)2 + (y + 3)² = 2
OB. (x-3)2 + (y-1)² = 2²
O c. (x-1)2 + (y - 3)² = 4
O D. (x+3)2 + (y + 1)² = 4
10

Answer 1

`\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{h}{3}~~,~~\underset{k}{1})} \qquad \stackrel{radius}{\underset{r}{2}} \\\\[-0.35em] ~\dotfill\\\\( ~~ x - 3 ~~ )^2 ~~ + ~~ ( ~~ y-1 ~~ )^2~~ = ~~2^2\implies (x -3)^2 + (y -1)^2 = 4`