Final answer:
The process of designing a controller for a vending machine with given specifications using a Mealy design with J-K flip-flops is explained step by step. This includes creating a state diagram, transition table, next-state table, deriving Boolean equations, and implementing and testing the circuit. It also addresses the requirement for a Not gate on the clock input of the strobed D flip-flop based on the edge behavior of the state memory and output signal.
Step-by-step explanation:
Step 1: State Diagram
In this vending machine design, we have the following states:
- S0: Idle state
- S1: Waiting for a nickel
- S2: Waiting for a dime
- S3: Dispensing taco and change
The state diagram would look like:
Step 2: Transition Table
To design the transition table, we need to determine the next state based on the current state and input. In this case, the inputs are 'nickel' and 'dime'. The transition table would look like:
Current StateInputNext StateS0nickelS1S0dimeS2S1nickelS2S1dimeS3S2nickelS1S2dimeS3S3nickelS3S3dimeS3
Step 3: Next-State Table
In this step, we determine the next state outputs based on the current state and input. The next-state table would look like:
Current StateInputNext StateOutputS0nickelS1No outputS0dimeS2No outputS1nickelS2No outputS1dimeS3No outputS2nickelS1No outputS2dimeS3No outputS3nickelS3Dispense taco and changeS3dimeS3Dispense taco and change
Step 4: Derive Boolean equations
From the next-state table, we can derive Boolean equations for each flip-flop. Let's assume Q0, Q1, and Q2 are the outputs of J-K flip-flops connected to S0, S1, and S2 states respectively. The Boolean equations would be:
- J0 = Q1' + Q2
- K0 = Q0
- J1 = Q0' + Q2
- K1 = Q1
- J2 = Q0' + Q1'
- K2 = Q2
Step 5: Implement and test circuit
Implement the circuit using LogicWorks chip schematics or on a breadboard according to the derived Boolean equations and the given specifications. Test the circuit to ensure it functions correctly.
Regarding the Not gate on the clock input of the strobed D flip-flop, it depends on the edge behavior of the state memory and output signal. If they are positive-edge triggered, you will need a Not gate on the clock input. If they are negative-edge triggered, a Not gate is not required.