Question

Please help I will give you any award

Answer 1

Check the picture below.

so let's find the height "h" of the triangle with base of 14.

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=√(c^2 - a^2) \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=√( 32^2 - 7^2)\implies h=√( 1024 - 49 ) \implies h=√( 975 )\implies h=5√(39) \\\\[-0.35em] ~\dotfill`

`\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5√(39)})}\implies 35√(39) ~~ \approx ~~ \text{\LARGE 218.57}`

Answer 2

218.57

Explanation:

Since it is an isoceles triangle, the sides are 32, 32, and 14.

Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2, we can calculate the area.

(A+B+C)/2 = (32+32+14)/2=39.

A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.

Hope this helps have a great day :)