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A three-phase 440-V, 51-kW, 60-kVA inductive load operates at 60 Hz and is Y-connected. It is desired to correct the power factor to 0.95 lagging. What value of capacitor should be placed in parallel with each load impedance?

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User Caco
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Final answer:

To correct the power factor to 0.95 lagging in a three-phase, Y-connected inductive load, capacitors should be placed in parallel with each load impedance.

Step-by-step explanation:

To correct the power factor to 0.95 lagging in a three-phase, Y-connected inductive load, a capacitor should be placed in parallel with each load impedance.

The power factor is given by the equation:

power factor = R / Z

where R is the resistance and Z is the impedance.

For unity power factor, the reactive power should be 0. To achieve this, the reactive power from the capacitors should cancel out the reactive power of the inductive load.

The reactive power Q of the inductive load can be calculated using:

Q = √(V^2 - P^2)

where V is the voltage and P is the active power.

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User Joe Bloggos
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