asked 33.4k views
3 votes
A^(m+4)*b^(2n+3)-3a^(m+1)*b^(n+2)
100 points for this

1 Answer

4 votes

Answer:

A^m * (A^4b^2)^n * b^3 - 3 * a^(m+1) * b^(n+2)

Explanation:

It looks like you have an expression with two terms, each containing variables raised to different exponents. Let's break down each term and see if we can simplify it.

Term 1: A^(m+4)*b^(2n+3)

This term contains two factors: A raised to the power of m+4, and b raised to the power of 2n+3. To simplify this term, we can use the rule that says a^(m+n) = a^m * a^n. Applying this rule, we have:

A^(m+4)*b^(2n+3) = A^m * A^4 * b^(2n) * b^3 = A^m * (A^4 * b^2n) * b^3 = A^m * (A^4b^2)^n * b^3

So, we can simplify the first term to:

A^m * (A^4b^2)^n * b^3

Term 2: -3a^(m+1)*b^(n+2)

This term also contains two factors: a raised to the power of m+1, and b raised to the power of n+2. To simplify this term, we can factor out a common factor of a^(m+1) and b^(n+2):

-3a^(m+1)*b^(n+2) = -3 * a^(m+1) * b^(n+2)

So, we can simplify the second term to:

-3 * a^(m+1) * b^(n+2)

Putting it all together, the original expression can be simplified to:

A^m * (A^4b^2)^n * b^3 - 3 * a^(m+1) * b^(n+2)

answered
User Gardni
by
8.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.