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What is the frequency of a photon if the energy is 5.27 × 10⁻¹⁹ J? (h = 6.626 × 10⁻³⁴ J • s)

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User Ebpa
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Answer:

To calculate the frequency of a photon with energy of 5.27 × 10⁻¹⁹ J, we can use the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.626 × 10⁻³⁴ J • s), and f is the frequency of the photon. Solving for f, we get:

f = E/h = (5.27 × 10⁻¹⁹ J)/(6.626 × 10⁻³⁴ J • s) = 7.95 × 10¹⁴ Hz

Therefore, the frequency of the photon is 7.95 × 10¹⁴ Hz.

Step-by-step explanation:

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User P Roitto
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