Question

How tall is the statue, and what is the diagonal distance from the man's eyes to the top of the statue? (Round your answers to the nearest tenth of a foot)

Answer 1

Check the picture below.

`\tan(56^o )=\cfrac{\stackrel{opposite}{y}}{\underset{adjacent}{84}} \implies 84\tan(56^o)=y \implies 124.5\approx y~\hfill~\boxed{y+6\approx 130.5} \\\\[-0.35em] ~\dotfill\\\\ \cos(56^o )=\cfrac{\stackrel{adjacent}{84}}{\underset{hypotenuse}{x}} \implies x\cos(56^o)=84\implies x=\cfrac{84}{\cos(56^o)}\implies \boxed{x\approx 150.2}`

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