Question

Balance the combustion reaction in order to answer the question. Use lowest whole-number coefficients. combustion reaction: A conbustion reaction occurs between 1.0 molO2​ and 105 gC2​H4​. Upon completion of the reaction, is there any C2​H4​ remaining? No, all of the C2​H4​ is used up in the reaction. Yes, there is still C2​H4​ remaining.

Answer 1

After balancing the combustion reaction for ethylene (C2H4), it is evident that 3.75 moles of C2H4 would require 11.25 moles of O2 for complete combustion. As only 1.0 mole of O2 is available, there will be remaining unreacted C2H4 after the reaction.

Step-by-step explanation:

To answer whether there will be any C2H4 remaining after the reaction with 1.0 mol O2, we first need to balance the combustion reaction. The combustion of ethylene (C2H4) produces carbon dioxide (CO2) and water (H2O). The balanced equation is:

• C2H4 + 3O2 → 2CO2 + 2H2O

Now we determine if the amount of O2 provided is sufficient to combust 105 g of C2H4. The molar mass of C2H4 is approximately 28 g/mol, thus 105 g corresponds to approximately 3.75 moles of C2H4. As the balanced equation shows, one mole of C2H4 requires 3 moles of O2 for complete combustion. Therefore, 3.75 moles of C2H4 would require 11.25 moles of O2. Since only 1.0 mole of O2 is available, there will not be enough oxygen to react with all of the ethylene, and some C2H4 will remain unreacted after the completion of the reaction.

Answer 2

After balancing the combustion reaction of ethylene (C2H4), we find that there's insufficient oxygen (O2) to completely react with the given amount of C2H4, thus some C2H4 remains.

Step-by-step explanation:

Combustion Reaction of Ethylene (C2H4)

To determine whether any ethylene (C2H4) remains after the reaction with oxygen (O2), we first need to balance the combustion reaction. Ethylene combines with oxygen to produce carbon dioxide (CO2) and water (H2O). The balanced chemical equation is:

C2H4 + 3O2 → 2CO2 + 2H2O

From the balanced equation, we can see that each mole of C2H4 requires 3 moles of O2 to react completely. Given that we have 1.0 mol O2 available, and the molar mass of C2H4 is 28 grams per mole, let's calculate how many moles of C2H4 we have in 105 grams:

105 g C2H4 × (1 mol C2H4 / 28 g) = 3.75 mol C2H4

Since 3.75 mol of C2H4 would require 3 × 3.75 = 11.25 mol of O2 to react completely, and we only have 1.0 mol of O2, not all C2H4 will be consumed in the combustion. Therefore, yes, there is still C2H4 remaining after the reaction.