Question

Answer Questions below

Answer 1

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1) V= 60 volt

Total resistance R = R₁ + R₂

= 20 + 10

= 30 Ω

2) Ohms law states that,

`\sf I =(V)/(R)\\\\\\I = (60)/(30)\\\\I = 2 \ A`

3) Voltage around 10 Ω resistor,

V₂ = I R₂

= 2 * 10

= 20 volt

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4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

R₁ = 2 Ω ; I = 1 A

V₁ = IR₁

= 1 * 2

= 2 volt

7) Resistance 2:

Total resistance = R

Total voltage = V = 8 volt

Total current = I = 1 A

`\sf R = (V)/(I)\\\\\\ R = (8)/(1)\\\\`

R = 8 Ω

R₁ + R₂ = 8 Ω

2 + R₂ = 8

R₂ = 8 - 2

R₂ = 6 Ω

8)Voltage around R₂:

`\sf V_2 = IR_2\\\\V_2 = 1*6\\\\`

V₂ = 6 volt

9) Total R = 8 Ω

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10) Total V = 12 volt

11) Total R = 8 + 8

= 16 Ω

12) Total current I,

`\sf I = (V)/(R)\\\\I = (12)/(16)\\\\I = 0.75 \ A`

13) Voltage at each resistor:

V₁ = I*R₁

= 0.75 * 8

= 6 volt

V₂ = I*R₂

= 0.75 * 8

= 6 volt

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14) Total R = 40 + 20

= 60 Ω

15) To find V₁, first find total voltage.

I = 2 A ; R = 60 Ω

V = IR

= 2 * 60

= 120 V

V₁ + V₂ =V

V₁ + 80 = 120

V₁ = 120 - 80

V₁ = 40 volt