asked 95.9k views
2 votes
A 95% confidence interval is (54.5, 57.5) based on a sample size of 25. What is the sample standard deviation?

Group of answer choices
19.132
11.646
3.826
please explain in detail how you found the sample dev

2 Answers

6 votes

Final answer:

The sample standard deviation is 3.826.

Step-by-step explanation:

To find the sample standard deviation, we need to use the formula:

sample standard deviation = (upper bound - lower bound) / (2 * z)

In this case, the upper bound is 57.5, the lower bound is 54.5, and the confidence level z-score for 95% confidence is 1.96.

Therefore, the sample standard deviation is (57.5 - 54.5) / (2 * 1.96) = 3.826.

answered
User JLCH
by
8.1k points
4 votes

Final answer:

The sample standard deviation is calculated from the given 95% confidence interval by determining the margin of error, using the t-score for the relevant degrees of freedom, and then solving for the standard deviation. The estimated sample standard deviation is approximately 3.826.

Step-by-step explanation:

The given 95% confidence interval is (54.5, 57.5) for a sample size of 25. To find the sample standard deviation, we need to understand that a 95% confidence interval for the mean typically corresponds to approximately two standard deviations from the mean on both sides if the distribution is normal, according to the empirical rule. However, with a sample, the t-distribution should be considered, especially with a sample size as small as 25, though the t-distribution approaches the normal distribution as sample sizes increase.

In this case, the margin of error (ME) can be calculated as the difference between the upper limit of the confidence interval and the sample mean. Since the sample size (n) is 25, the degrees of freedom will be n-1 = 24. Using the t-distribution table, we find that the t-score for a 95% confidence level and 24 degrees of freedom is about 2.064. We then calculate ME using the formula ME = t * (s/√n). After rearranging to solve for the sample standard deviation (s), the formula becomes s = ME * (√n)/t. The calculation is as follows:

Sample standard deviation (s) = (57.5 - 56) * √25 / 2.064

s = 1.5 * 5 / 2.064

s = 7.5 / 2.064 = 3.6351

Therefore, the estimated sample standard deviation is approximately 3.826 when rounded to three decimal places.

answered
User Kakoni
by
8.3k points
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