Question

S+3/s^2-1s-12 • s-4/6

Answer 1

`\displaystyle (1)/(6)`

Explanation:

`\displaystyle (s+3)/(s^2-s-12)\cdot(s-4)/(6)=((s+3)(s-4))/(6(s^2-s-12))=((s+3)(s-4))/(6(s+3)(s-4))=(1)/(6)`

Make sure when multiplying fractions that you multiply the numerators together and the denominators together separately.