Question

57. A man four times as old as his son. In 5 years he will be three times as old as his son. What is the present age of the son in years? A)8 b) 9 c) 10 d) 1​

Answer 1

O A. (F + 9) (=) = 12° + 222 _ 22 - 3
O B. (f + g) (2) =
-473 + 822 + 42 - 9
O C. (f + g) (x) = 423 - 422 + 42 - 3
〇 D.(f+g)(z) = 67'
_ 222
3

Answer 2

Explanation:

Let's assume the present age of the son is "x" years.

According to the given information, the man is four times as old as his son, so the present age of the man would be 4x years.

In 5 years, the man will be three times as old as his son.

So, after 5 years, the man's age will be (4x + 5) years, and the son's age will be (x + 5) years.

According to the second condition, the man's age after 5 years will be three times the son's age after 5 years:

4x + 5 = 3(x + 5)

let's solve the equation:

4x + 5 = 3x + 15

Subtracting 3x from both sides, we get:

x + 5 = 15

Subtracting 5 from both sides, we get:

x = 10

Therefore, the present age of the son is 10 years.

The correct answer is option c) 10.