asked 96.2k views
4 votes
On a test that has a normal distribution, a score of 66 falls two standard deviations

above the mean, and a score of 36 falls one standard deviation below the mean.
Determine the mean of this test.

asked
User Ken C
by
7.5k points

1 Answer

2 votes

- x: the mean of the test

- s: the standard deviation of the test

We know that a score of 66 falls two standard deviations above the mean, so we can write:

66 = x + 2s

Similarly, we know that a score of 36 falls one standard deviation below the mean, so we can write:

36 = x - s

Now we have two equations with two unknowns (x and s). We can solve for x by isolating it in one of the equations and then substituting the result into the other equation.

Let's start with the second equation:

36 = x - s

x = 36 + s

Now we can substitute this expression for x into the first equation:

66 = x + 2s

66 = (36 + s) + 2s

66 = 36 + 3s

30 = 3s

s = 10

We have found the value of the standard deviation to be 10. Now we can substitute this value into either of the original equations to find the mean:

x = 36 + s

x = 36 + 10

x = 46

Therefore, the mean of the test is 46.

answered
User Umer Waqas
by
6.9k points

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