Question

the perimeter of the rectangle playing field is 402 yards the length of the field is 4 yards less than quadruple the width. what are the dimensions of the field?

Answer 1

Length = 160 Width = 41

Explanation:

402 = 2L + 2w

L = 4w - 4

2(4w-4)+2w

8w-8+2w = 402

10w-8=402

10w = 410

w = 41

L = 4(41)-4

L = 160