Question

How would I find the slope of 6x+6y+11=0?

Answer 1

-1

Explanation:

Before finding the slope of the line, we have to rewrite its equation in the slope-intercept form, so in the form

y=mx+q(1)

Here the equation of the line is.

6x+6y+11=0

By manipulating the equation we find:

-6x-11=6y

y=-
`\frac{6x+11\\}6`

y=-x-11/6

So, the equation of the line in the slope-intercept form is

y=-x-11/6

And by comparing it with (1), we find:

m=-1

q=-11/6

So, the slope is -1, and the y-intercept is -11/6.

HOPE THIS HELPS ^^

Answer 2

The slope of a line can be found by rearranging the equation into slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

So, for the equation 6x + 6y + 11 = 0, we can rearrange it to get y = -x - 11/6. In this case, the slope m is -1. So the slope of the line 6x + 6y + 11 = 0 is -1.