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What volume, in liters, will contain 1.21 × 10^21 neon atoms at STP?

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To determine the volume that will contain a given number of atoms at STP (Standard Temperature and Pressure), we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)

At STP, the temperature is 273.15 Kelvin, and the pressure is 1 atmosphere.

To find the volume, we need to convert the number of neon atoms to moles:

Number of moles (n) = Number of atoms / Avogadro's number

Avogadro's number is approximately 6.022 × 10^23 mol^-1.

Let's calculate the volume using the given information:

Number of atoms = 1.21 × 10^21
Number of moles (n) = (1.21 × 10^21) / (6.022 × 10^23)
Temperature (T) = 273.15 Kelvin
Pressure (P) = 1 atmosphere
Ideal gas constant (R) = 0.0821 L·atm/(mol·K)

Now, we can rearrange the ideal gas law equation to solve for volume (V):

V = (nRT) / P

Let's substitute the values into the equation and calculate the volume:

V = [(1.21 × 10^21) / (6.022 × 10^23)] × (0.0821) × (273.15) / (1)

After performing the calculation, the volume would be approximately equal to 2.05 liters.
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User RobDil
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