Answer: 10.20.
Step-by-step explanation:
The pH of a solution with a fluoride concentration of 0.24 M can be calculated using the following steps:
1. Calculate the pOH of the solution using the Kb of F: pOH = -log(Kb) = -log(1.47x10^-11) = 10.83
2. Calculate the concentration of H+ ions in the solution using the pOH: [H+] = 10^-pOH = 6.309x10^-11 M
3. Calculate the pH of the solution using the concentration of H+ ions: pH = -log[H+] = -log(6.309x10^-11) = 10.20
Therefore, the pH of the solution is 10.20.