Final answer:
The angular acceleration of the phonograph record is 0.974 rad/s². It goes through approximately 0.718 revolutions.
Step-by-step explanation:
(a) What is its angular acceleration in rad/s²?
To find the angular acceleration, we can use the formula:
Angular acceleration = (final angular velocity - initial angular velocity) / time
Given that the initial angular velocity is 0 and the final angular velocity is 43.0 rpm (which is equivalent to 4.506 rad/s), and the time is 4.63 s, we can substitute these values into the formula:
Angular acceleration = (4.506 rad/s - 0 rad/s) / 4.63 s = 0.974 rad/s²
Therefore, the angular acceleration is 0.974 rad/s².
(b) How many revolutions does it go through in the process?
To find the number of revolutions, we can use the formula:
Number of revolutions = final angular velocity / (2π)
Substituting the values, we get:
Number of revolutions = 4.506 rad/s / (2π) = 0.718 revolutions
Therefore, it goes through approximately 0.718 revolutions.