Question

Help me please .
i need to submit the homework today .

Answer 1

D. 0.010 m

Step-by-step explanation:

wavelength
`\lambda` =
`570 nm = 570 nm * (1 m / 10^9 nm) = 5.7 * 10^(-7)m`

width(d)=
`0.0900 mm * (1 m / 1000 mm) = 9.00 * 10^(-5) m`

distance(L)=0.800 m

The width of the central bright band is given by the equation:

`w = (2\lambda L)/(d)`

where
`$\lambda$` is the wavelength of light,
`$L$` is the distance from the slit to the screen, and
`$d$` is the width of the slit.

Substituting the given values, we get:

`w = \frac{2(5.70 * 10^(-7) \text{ m})(0.800 \text{ m})}{9.00 * 10^(-5) \text{ m}} = 0.010 \text{ m}`

Therefore, the width of the central bright band is
`\boxed{0.010 \text{ m}}`