Answer:
d. 0
Explanation:
To solve the given trigonometric equation, let's use the trigonometric identity: sin²θ + cos²θ = 1. We can rewrite the equation provided as follows:
cos a + cos² B + cos² y = 3
Using the identity, we can rewrite it as:
1 - sin² a + 1 - sin² B + 1 - sin² y = 3
Simplifying further, we have:
3 - (sin² a + sin² B + sin² y) = 3
Rearranging the equation, we get:
sin² a + sin² B + sin² y = 3 - 3
sin² a + sin² B + sin² y = 0
Therefore, the value of sin² a + sin² B + sin² y is 0 (option d).