67 L of N2 gas at STP is equivalent to 2.67 moles of N2 ga
Steps
To calculate the number of moles of N2 gas, we can use the ideal gas law:
PV = nRT
where:
P is the pressure of the gas
V is the volume of the gas
n is the number of moles of gas
R is the universal gas constant
T is the temperature of the gas in kelvin
Assuming standard temperature and pressure (STP), the pressure is 1 atmosphere and the temperature is 273 K. The volume of gas is 67 L.
So, we have:
PV = nRT
n = (PV) / (RT)
n = (1 atm) x (67 L) / ((0.0821 L·atm/mol·K) x (273 K))
n = 2.67 mol
Therefore, 67 L of N2 gas at STP is equivalent to 2.67 moles of N2 gas.