Question

In each of the following equction. density the Substance oxidized reduced • the Oxidizing agen & reducing a sent 3cu+8HNO3→3cu (NO3)4+NO​

Answer 1

1. Substance oxidized: Cu (copper)
2. Substance reduced: HNO3 (nitric acid)
3. Oxidizing agent: HNO3 (nitric acid)
4. Reducing agent: Cu (copper)

Explanation: In this equation, copper (Cu) is oxidized and nitric acid (HNO3) is reduced. The oxidation state of Cu increases from 0 to +2, while the oxidation state of nitrogen (N) in HNO3 decreases from +5 to +2. Thus, HNO3 acts as an oxidizing agent, while Cu acts as a reducing agent. The product formed is copper nitrate (Cu(NO3)2) and nitrogen monoxide (NO).

Note: The density of the substances is not relevant to the identification of the substance oxidized, substance reduced, oxidizing agent, and reducing agent in this equation.