asked 53.3k views
0 votes
A solution of copper sulfate is treated with zinc metal. How many grams of copper are produced if 2.9 g of zinc are consumed? (Hint: Make sure to balance the equation first)

Select one:

a.
2.9 g

b.
2.8 g

c.
5.7 g

d.
3.7 g

asked
User Mtflud
by
7.7k points

1 Answer

2 votes

Answer:

b. 2.8

Step-by-step explanation:

To determine the amount of copper produced, we need to first balance the chemical equation for the reaction between copper sulfate and zinc. The balanced equation is as follows:

Zn + CuSO4 → ZnSO4 + Cu

From the balanced equation, we can see that 1 mole of zinc (Zn) reacts with 1 mole of copper sulfate (CuSO4) to produce 1 mole of copper (Cu). The molar mass of zinc is 65.38 g/mol, and the molar mass of copper is 63.55 g/mol.

Given that 2.9 g of zinc is consumed, we can calculate the moles of zinc:

moles of zinc = mass of zinc / molar mass of zinc

= 2.9 g / 65.38 g/mol

≈ 0.0443 mol

Since the reaction is 1:1 between zinc and copper, the moles of copper produced will be the same as the moles of zinc consumed. Therefore, 0.0443 mol of copper is produced.

Now, we can calculate the mass of copper:

mass of copper = moles of copper × molar mass of copper

= 0.0443 mol × 63.55 g/mol

≈ 2.81 g

Therefore, the correct answer is b. 2.8 g

chatgpt

The balanced equation for the reaction is:

Zn + CuSO4 -> ZnSO4 + Cu

This means that 1 mole of zinc reacts with 1 mole of copper sulfate to produce 1 mole of zinc sulfate and 1 mole of copper.

The molar mass of zinc is 65.38 g/mol, and the molar mass of copper is 63.55 g/mol.

Therefore, 2.9 g of zinc is equivalent to 0.044 moles of zinc.

This means that 0.044 moles of copper will be produced.

The molar mass of copper is 63.55 g/mol, so 0.044 moles of copper is equivalent to 2.8 g of copper.

Therefore, 2.8 g of copper will be produced.

So the answer is (b).

bardAI

answered
User RamonBoza
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.