Question

Blake bike east at 5m/s. five seconds later he speeds up to 9 m/s.

what is his change in velocity? what is his acceleration?

Answer 1

The answer is down below

Explanation:

v-u=◇velocity

`= 9 - 5`

◇velocity =4ms‐¹

acceleration =◇velocity/time

`a = (4)/(5)`

`a = 0.8m {s}^( - 2)`

Answer 2

Change in velocity:

`\sf \:final \: velocity - initial \: velocity = change \: in \: velocity`

`\therefore \tt \delta \: v = 9 - 5 \\ \tt = 4m {s}^( - 1)`

To find acceleration:

`\rm \: a = ( \triangle \: v)/(\triangle \: t)`

`\rm \: a = ( 4)/(5 - 0) = (4)/(5) = 0.8m {s}^( - 1)`