Answer: The probability of the first player being the center fielder is 1 out of 9 because there is only one center fielder on the team.
After the center fielder is chosen, there are 8 players remaining, and the probability of the second player being the shortstop is 1 out of 8 because there is only one shortstop on the team.
To calculate the probability of both events occurring in order, we multiply the individual probabilities:
Probability = (1/9) * (1/8) = 1/72
Therefore, the probability that the first two players in the lineup will be the center fielder and the shortstop, in that order, is 1 out of 72.