Question

Find the number of distinct arrangements of the 9 letters in CHOCOLATE.

Two of the same letter are considered identical (not distinct).

Answer 1

If all letters were distinct, there would have been 9! = 362880 arrangements.

Since there are 2 C's and 2 O's (and 1 A, E, H, L and T), there are 9!/2!/2! = 90720 arrangements.