Question

How many total atoms are in 0. 440 g of P2O5

Answer 1

First of all find moles of P2O5

`\tt Moles = (given \: weight)/(molecular \: mass)`

`\tt Moles = (0.440)/(142)`

`\tt Moles = 0.003`

Multiply it by avogadro number to find atoms:

`\sf \: 0.003 * 6.023 * {10}^( - 23)`

`\sf \: 1.8 * {10}^( - 25)`