Question

A crane lifts the 18000 kg steel hull of a sunken ship out of the water. Determine the tension in the crane's cable when the hull is fully submerged in the water

Answer 1

When the hull is fully submerged in water, the tension in the crane's cable will be 352,800 N.

Step-by-step explanation:

To determine the tension in the crane's cable when the hull is fully submerged in the water, we need to consider the forces acting on the hull. When submerged, the buoyant force exerted by the water on the hull is equal to the weight of the water displaced by the hull. Since the hull weighs 18,000 kg, the buoyant force will also be 18,000 kg times the acceleration due to gravity. The tension in the crane's cable will be equal to the sum of the weight of the hull and the buoyant force, which is given by the equation:

Tension = Weight of Hull + Buoyant Force

Tension = (mass of hull x g) + (mass of water displaced x g)

Tension = (18,000 kg x 9.8 m/s²) + (18,000 kg x 9.8 m/s²)

Tension = 176,400 N + 176,400 N

Tension = 352,800 N

Answer 2

A crane lifts the 18000 kg steel hull of a sunken ship out of the water. The tension in the crane's cable when the hull is fully submerged in the water is 1764000 N.

Step-by-step explanation:

To determine the tension in the crane's cable when the hull is fully submerged in the water, we can use the principle of buoyancy. The buoyant force is equal to the weight of the water displaced by the submerged hull. The maximum buoyant force is ten times the weight of the steel, so we can calculate the weight of the steel hull and multiply it by ten to find the tension in the crane's cable.

Given that the weight of the steel hull is 18000 kg, we can calculate its weight using the equation W = m * g, where W is the weight, m is the mass, and g is the acceleration due to gravity.

Assuming g is approximately 9.8 m/s² the weight of the steel hull is 18000 kg * 9.8 m/s² = 176400 N.

Multiplying this weight by ten gives us the tension in the crane's cable:

176400 N * 10 = 1764000 N.