asked 171k views
3 votes
How many molecules of. C6H1206 are needed to produce 18 molecules of co2

A.3

B.9

C.12

D.18

2 Answers

7 votes

Answer:

A = 3.

Step-by-step explanation:

Here is how:

To determine the number of molecules of C6H12O6 (glucose) needed to produce 18 molecules of CO2, we need to consider the balanced chemical equation for the complete combustion of glucose:

C6H12O6 + 6O2 -> 6CO2 + 6H2O

From the balanced equation, we can see that 1 molecule of glucose (C6H12O6) produces 6 molecules of CO2. Therefore, we can set up a proportion to find the number of glucose molecules needed:

1 molecule of glucose produces 6 molecules of CO2

x molecules of glucose produce 18 molecules of CO2

Using the proportion:

1/6 = x/18

To solve for x, we can cross-multiply:

6x = 18

Dividing both sides by 6:

x = 3

Therefore, 3 molecules of C6H12O6 are needed to produce 18 molecules of CO2.

answered
User Kimi
by
7.8k points
4 votes

Answer: A : 3

Explanation: 18 CO2 / 6 CO2 = 3 C6H12O6

answered
User Jim Ingham
by
8.7k points
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