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5 votes
Factorise fully 72 - 2y^2

asked
User KanUXD
by
8.5k points

2 Answers

3 votes

Find the GCF of the terms: 72 and -2y^2.


  • The GCF of 72 and -2y^2 is 2.


Divide
each term by the GCF:

  • 72 ÷ 2 = 36
  • -2y^2 ÷ 2 = -y^2

Now we have: 2(36 - y^2).

Identify if there is a difference of squares.

  • In this case, 36 - y^2 can be factored as (6 - y)(6 + y) since it follows the difference of squares pattern: (a^2 - b^2) = (a - b)(a + b).

Putting it all together, the fully factorized expression is:


2(6 - y)(6 + y).

answered
User OGHaza
by
7.8k points
3 votes


72 - 2y^(2) = 2(36-y^(2) )= 2(6-y)(6+y)

answered
User Tassadaque
by
8.4k points

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