Question

A metalrod of length 40.0cm at 20°C is heated to a temperature of 45°C. If the new length is 40.05cm, Calculate its Linear expansivity.​

Answer 1

The answer is 5×10‐⁵

Explanation:

`\alpha = (l2 - l1)/(l1( \beta 2 - \beta 1))`

let ß be ø

`\alpha = (40.05 - 40)/(40(45 - 20))`

`\alpha = (0.05)/(40 * 25)`

`\alpha = (0.05)/(1000)`

`\alpha = (0.05)/(1000)`
`\alpha = 5.0 * {10}^( - 5)`