Question

Your portfolio must include a minimum of the following five types of equations and solutions:

Two one-step equations
Two equations that contains fractions
One equation with distributive property
One equation with decimals
One real-world problem that is solved by an equation
Remember that each equation must include at least one variable. Once you have created each equation, you will solve it and show your work. Pretend that you are teaching the equations to a new pre-algebra student. Or you can actually teach them to a sibling or friend!

This is a total of 7 equations and solutions.

Answer 1

Explanation:

A. x + 5=12

7x = 21

B. b - 2/3 = 5/6

1/5m = 20

C. 45 = 3(x + 1)

D. 22.5 = 1.5x

E. Mark has $20 in his bank account. He saves $5 each week. How much money does Mark have in his account after 9 weeks? Use w to represent the number of weeks and t to represent the total amount Mark has after any number of weeks.

Answer 2

certainly use these examples to practice solving equations yourself! Here are some equations that meet the criteria you provided:

1) One-step equation:
5x + 3 = 18
Solution:
Subtract 3 from both sides to isolate the variable:
5x + 3 - 3 = 18 - 3
5x = 15
Divide both sides by 5 to solve for x:
5x/5 = 15/5
x = 3

2) One-step equation:
4y - 7 = 9
Solution:
Add 7 to both sides to isolate the variable:
4y - 7 + 7 = 9 + 7
4y = 16
Divide both sides by 4 to solve for y:
4y/4 = 16/4
y = 4

3) Equation with fractions:
2/3 x + 1/4 = 1/2
Solution:
Subtract 1/4 from both sides to isolate the variable:
2/3 x + 1/4 - 1/4 = 1/2 - 1/4
2/3 x = 1/4
Multiply both sides by 3/2 to solve for x:
(2/3 x) * (3/2) = (1/4) * (3/2)
x = 3/8

4) Equation with fractions:
3/4 z - 1/2 = 1/8
Solution:
Add 1/2 to both sides to isolate the variable:
3/4 z - 1/2 + 1/2 = 1/8 + 1/2
3/4 z = 5/8
Multiply both sides by 4/3 to solve for z:
(3/4 z) * (4/3) = (5/8) * (4/3)
z = 5/6

5) Equation with distributive property:
2(x + 5) = 16
Solution:
Use the distributive property to simplify the left side of the equation:
2(x + 5) = 2x + 10
Subtract 10 from both sides to isolate the variable:
2x + 10 - 10 = 16 - 10
2x = 6
Divide both sides by 2 to solve for x:
2x/2 = 6/2
x = 3

6) Equation with decimals:
0.5x + 1.25 = 2.75
Solution:
Subtract 1.25 from both sides to isolate the variable:
0.5x + 1.25 - 1.25 = 2.75 - 1.25
0.5x = 1.5
Divide both sides by 0.5 to solve for x:
0.5x/0.5 = 1.5/0.5
x = 3

7) Real-world problem:
You have $50 to spend on tickets to a concert that costs $10 per ticket. How many tickets can you buy?
Solution:
Let x be the number of tickets you can buy. The total cost of the tickets is 10x. We know that the total cost


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