Question

At the movie theatre, child admission is $6.30 and adult admission is $9.80. On Monday, twice as many adult tickets as child tickets were sold, for a total sales of $673.40. How many child tickets were sold that day?

Answer 1

Answer:We can solve this problem by using algebra. Let × be the number of child tickets sold and y be the number of adult tickets sold. We know that y = 2x (twice as many adult tickets as child tickets were sold) and that the total amount of money made from ticket sales was $278.20.

So we can write the equation 6.3x + 9.8y =

278.2 and substitute y = 2x into it to get 6.3x +

9.8(2x) = 278.2.

Simplifying this expression gives us 6.3x + 19.6x = 278.2.

Combining like terms gives us 25.9x = 278.2.

Solving for x gives us x = 10.74.

Since we can't sell a fraction of a ticket, we round up to 11 child tickets.

We know that y = 2x, so y = 2(11) = 22.

So 11 child tickets and 22 adult tickets were sold.

Answer 2

26 child tickets

Explanation:

Let's assume the number of child tickets sold is "x".

According to the given information, the number of adult tickets sold is twice the number of child tickets sold, so the number of adult tickets sold would be "2x".

The total sales from child tickets can be calculated by multiplying the number of child tickets by the child admission price:

Total sales from child tickets = $6.30 * x

Similarly, the total sales from adult tickets can be calculated by multiplying the number of adult tickets by the adult admission price:

Total sales from adult tickets = $9.80 * (2x)

The total sales from both child and adult tickets is given as $673.40:

Total sales from child tickets + Total sales from adult tickets = $673.40

Substituting the expressions for the total sales:

$6.30 * x + $9.80 * (2x) = $673.40

Simplifying the equation:

6.30x + 9.80(2x) = 673.40

6.30x + 19.60x = 673.40

25.90x = 673.40

Dividing both sides by 25.90:

x = 26

Therefore, 26 child tickets were sold on Monday.